The brakes applied to a car produce an
acceleration of 4 m/s2 in the opposite direction to the
motion. If the car takes 3 s to stop after the application
of brakes, calculate the distance it travels during this
time.
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Answer:
➡️ as the car produces acceleration in opposite direction, acceleration= -4m/S2
➡️ final velocity, v= 0m/s (as the car stops)
➡️ time = 3s
according to the formula
v = u + at
we have,
u = v - at = 0 - (-4×3) m/s
that is, u = 12 m/s
according to the formula
s = ut + 1/2 at2
we have,
s = (12×3 + 1/2×-4×3×3)m
that is, s = (36-18) m
that is, s = 18 m
hence, the distance the car travels during this time is 18 m
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