the brakes applied to a car produce an acceleration of 5 metre per second square in the opposite direction of motion if the car takes 3 seconds to stop after the application of brakes then calculate the distance it travels during this time
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a=-5 m/s^2
t=3
v=0
we know that
v=u+at
0=u-5*3
u=15 m/s
also
v²-u²=2as
0-225=2*(-5)*s
s=22.5 m
hope this helps
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