The brakes applied to a car produce an acceleration of 5ms-2 in the opposite direction to the motion. If the car takes 5s to stop after the application of brakes, calculate the distance it travels during this time.
Answers
Answered by
12
given,
a=-5
t=5s
v=0
S=?
v-u=at
-u=5×-5
=>u=25
v^2-u^2=2aS
=>-625=2×-5×S
=>S=62.5m
hope it helps u
mark braniest plzzzzzzzzz
a=-5
t=5s
v=0
S=?
v-u=at
-u=5×-5
=>u=25
v^2-u^2=2aS
=>-625=2×-5×S
=>S=62.5m
hope it helps u
mark braniest plzzzzzzzzz
Answered by
1
Answer:
=-5
t=5s
v=0
S=?
v-u=at
-u=5×-5
=>u=25
v^2-u^2=2aS
=>-625=2×-5×S
=>S=62.5m
Explanation:
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