the brakes applied to a car produce an acceleration of 6 metre per second in the opposite direction to the motion in the car takes 2 second to stop after the application of brakes calculate the distance travelled by the car during this time
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A=-6m/s^2
t=2sec
v=0m/s
u?
s?
v=u+at
u=v-at
u=0-(-6×2)
u=12m/s
s=v^2-u^2/2a
s= 0-144/-12
s=12m
hope it will help you..
t=2sec
v=0m/s
u?
s?
v=u+at
u=v-at
u=0-(-6×2)
u=12m/s
s=v^2-u^2/2a
s= 0-144/-12
s=12m
hope it will help you..
shalu266:
r u sure it's correct?
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