The brakes applied to a car produce
an acceleration of 6 m/s2 in the
opposite direction to the motion. If
the car takes 2 s to stop after the
application of brakes, calculate the
distance it travels during this time.
Answers
Answered by
1
Explanation:
this is because of the formula s(distance) = u(intial velocity) * time + 1/2a(acceleration) *t(time)sqaure
Attachments:
Answered by
3
Answer:
Acceleration= -6m/s^2 (given- in opp direction)
time= 2s
v= 0
a=v-u/t
-6=(0-u)/2
-12= -u
12= u
s=ut+1/2at^2
s= 12×2+ (-6) (4)
2
s= 24-12
s= 12km
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