Question

The brakes applied to a car produce an acceleration of 6 m//s^(2) in the opposite direction to the motion . If the car takes 2 s to stop after the application of brakes , calculate the distance it travels during this time.

Answer 1

Distance traveled during 2 sec is 12 m

Explanation:

Given, acceleration = -6 m s⁻² (as the direction is opposite)

time = 2 s

final velocity = 0 m s⁻¹

• Acceleration of the body is defined as the rate of change velocity. It is a vector quantity so the direction of acceleration is also considered during the motion
• In the given question as the final velocity becomes zero by the application of brakes so the body is retarding that is having negative acceleration

By using the first equation of motion we can calculate the initial velocity of the car v = u +a t

=> 0 = u + (-6) 2

=> u = 12 m s⁻¹

By using the second equation of motion we can calculate the distance traveled by car in 2 sec

=> s = u t +$\frac{1}{2}$ a t²

=> s = 12 (2) + $\frac{1}{2}$ (-6) 2²

=> s = 24 - 12

=> s = 12 m

To know more about equation of motion, visit:

Derive Newton's Third equation of motion with algebraic method

https://brainly.in/question/1296333

State three equation of motion. which of them describes (a) velocity -time relation (b) position -time relation please solved it

https://brainly.in/question/4161043

Answer 2

$\huge{\boxed{\mathcal\green{\fcolorbox{red}{yellow}{Answer}}}}$

The distance travelled in 2sec. is 12m