Question

The brakes applied to a car
produce an acceleration of 6 m/s
in the opposite direction to the
motion. If the car tare 25 sec
to stop/ after the application of
brakes, calculate the dist. it travel
during this time.​

Answer 1

Answer :

Given -

• Acceleration produced after applying brakes = -6 m/s
• Time taken to stop = 25 sec
• Final velocity = 0 m/s

To Find -

• Distance travelled during this time ?

Solution -

Using Newton's first equation of motion :

⇒ v = u + at

⇒ 0 = u + -6*25

⇒ 0 = u - 150

⇒ u = 150 m/s

Now, using Newton's second equation of motion :

⇒ s = ut + ½at²

⇒ s = 150*25 + ½*-6*25²

⇒ s = 3,750 + -3*625

⇒ s = 3,750 - 1,875

⇒ s = 1,875 m

Hence, Distance travelled after the application of the brakes = 1,875 m.