Question

The brakes applied to a car produce an acceleration of 6m./s in the opposite direction to the motion. If the car takes 2s to stop after the application of brakes, calculate the distance it travels during this time

Answer 1

Hey !!!!

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Acceleration : -6m/s^2

Time : 2s

Distance : s

Acceleration = Velocity/Time

Acceleration = Distance/Time

Acceleration × Time = Distance

-6m/s^2 × 2s = Distance

-12 m = Distance

But, Here minus sign Indicates opposite to the acceleration.

Hence,

Distance =+12 m

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Hope This Helps....!!!

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Answer 2

$\huge\mathfrak\pink{Solution}$

★ We know that

${ \ a \ = \ - 6 m s¯¹ \ ; \ t \ = \ 2s \ and \ v \ = 0 m </p><p> s¯¹}$

${ \ we \ know \ that}$

${ \ v \ = u \ + \ at}$

${ \ 0 \ + \ ( - 6 m s¯¹) \ × 2}$

or u = 12 m s¯¹

${ \ we \ get}$

${ \ s \ = \ ut \ +}$ $\frac{1}{2}$ ${ \ at²}$

${ \ (12 m s¯¹) \ × (2s) \ +}$ $\frac{1}{2}$ (-6m s¯¹) (2s)²

$\tt{\implies}$ ${ \ 24m \ - \ 12m}$

$\tt{\implies}$ ${ \ 12m}$

$\huge\mathfrak\pink{hope \ it's \ helps \ you}$