Question

the brakes applied to a car produce an acceleration of 6m/s in the opposite direction to motion, if the car takes 2s to stop after applying the brakes, calculate the distance it travels during this time.​

Answer 1

Answer:

given

acceleration = -6m/s^2

v= 0m/s

t = 2sec

v= u + at

0 = u+ -6*2

u = 12m/s^2

also,

s = ut +1/2at^2

s = 12*2 + 1/2*-6*2*2

s= 24 - 12

s = 12m

Explanation:

Answer 2

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Acceleration a = -6 m/s^2

Time t = 2 s

Final velocity v = 0 m/s

Let initial velocity be u

Let distance be s

v = u + at

So, 0 = u + (-6)(2)

So, u = 12 m/s

Now, s = ut + (1/2) at^2

So, s = 12(2) + (1/2)(-6)(2^2)

So, s = 24 - 12

So, s = 12 m

Thus, distance travelled is 12 m