the brakes applied to a car produce an acceleration of 6m/s2 in the opposite direction to the motion . if the car takes 2 s to stop after the application of brakes , calculate the distance it travel during this time.
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Answer:
12m
Explanation:
Given:
Accerleration: a=−6 m/s
2
Time t=2 s
Final velocity, v=0 m/s
v=u+at
0=u−6×2
u=12 m/s
s=ut+
2
1
at
2
s=12×2+
2
1
×(−6)×4
⇒s=12 m
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