Question

The brakes applied to a car produce an
accelration Of 6m/s in opposite directon to
the motion. If the car takes 2s to Stop
after application of breaks the distance It
travels during this time.
​

Answer 1

a=-6m/s2

t=2 sec

v=0m/s

v=u+at

0=u+-6×2

-u=-12

so,u=12 m/s

$2as = v ^{2} - u ^{2}$

2×-6×s=(0)2-(12)2

-12s=0-144

-12s=-144

s=-144/-12

s=12m

Answer 2

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