Question

The brakes applied to a carproduce an acceleration of 6 m sº inthe opposite direction to the motion. Ifthe car takes 2 s to stop after theapplication of brakes, calculate thedistance it travels during this time..​

Answer 1

Answer: 12m

Explanation:

Acceleration, a=-6m/s^2 (Since the breaks are applied which oppose the motion therefore the car is retarding)

Time,t=2s

Final Velocity, v=0m/s (The car comes to rest after breaks are applied)

We know that v=u+at

0=u+(-6)(2)

u=12m/s

We also know that v^2-u^2=2aS

-144=2(-6)(S)

S=12m

Hope my answer helps :)