Question

The brakes are applied to a moving car producing a negative acceleration of 2m/s square and the car stops after 6s The distance traveled by the car applying brakes

Answer 1

a=-2m/s^2
t=6sec
v=0( as car stops )
v-u\t = a( by this find u that uh will get as 12)
u=12m/s
s=ut+1/2at^2 ( find s)
s=36m


Hope uh understand !

Answer 2

acceleration = 2m/s square
time=6s
distance = to be calculated
initial velocity = o
s=ut+1/2at square
s= (0)×6+1/2 6×2
s=6m