Question

The brakes are applied to a train moving at 90 km per hr produces a retardation of 5 m per second square. What distance will it cover before coming to a stop.

Answer 1

Hi friend
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Your answer
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Initial velocity = u = 90 km/h = 20 m/s

Final velocity = v = 0 m/s

Acceleration = a = - 5 m/s²

Distance covered before coming to rest = s = ?

So,
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v² - u² = 2 × a × s

=> (0)² - (20)² = 2 × (- 5) × s

=> - 400 = - 10s

=> 400 = 10 s

=> s = 400/10

=> s = 40 m

Therefore,
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The train covers a distance of 40 m before coming to a stop.

HOPE IT HELPS

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Answer 2

initial velocity =90k\h=25m\s
final velocity =0m\s
acceleration =-5m\s^2
v^2-u^2=2as
-625=-10s
s=62.5m