Question

the brakes are applied to a train moving at 90km/h produce a retardation of 5m/s. what distance will it cover before coming to a stop ?

Answer 1

a = -5 m/s²
u = 90 kmph = 90×5/18 = 25 mps
v = 0

Using 2nd equation of uniformly accelerated motion.
${v}^{2} = {u}^{2} + 2as \\ 0 = 625 + (2 \times - 5 \times s) \\ - 625 = - 10s \\ s = 62.5 \: metres$
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Answer 2

Answer:A = -5 m/s²

u = 90 kmph = 90×5/18 = 25 mps

v = 0

Using 2nd equation of uniformly accelerated motion.

{v}^{2} = {u}^{2} + 2as \\ 0 = 625 + (2 \times - 5 \times s) \\ - 625 = - 10s \\ s = 62.5 \: metres

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Explanation: