The breadth of a rectangle is 6 cm and each of its diagonal measures 10cm.find its length?
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since the diagonal is given a triangle is formed so that the diagonal is the hypotenuse of the triangle.so let AB = lenght, BC= 6 cm = breadth,AC= 10cm = hypotenuse
according to pythagoras theorem
AC^2 = AB^2 +BC^2
10^2 = 6^2 + AB^2
100 = 36 +AB^2
64 = AB^2
AB = 8
lenght of the rectangle = 8 cm
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sorry my bro wrote it sorry
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