Question

The breadth of a rectangular field is twice its length. If the area of the field is 1058 m², find the cost of
fencing it at rupees 35 per m.
​

Answer 1

Answer:

4830 Rs.

Step-by-step explanation:

Consider length of the rectangular field = l meters,

∵ Breadth is twice its length.

So, width = 2l,

Thus, area = length × width

= l × 2l

= 2l²

According to the question,

2l^2 = 10582l

2

=1058

l^2 =\frac{1058}{2}l

2

=

2

1058

l^2 = 529l

2

=529

\implies l =\sqrt{529}=23⟹l=

529

=23 ( Negative value will not consider because side can not be negative )

That is,breadth = 2(23) = 46,

Hence, perimeter of the field = 2(length + breadth) = 2(23+46) = 2(69) = 138 meters,

If cost of fencing for 1 meter = 35 rupees,

Then the cost of fencing 138 meters = 138 × 35 = 4830 rupees.

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Answer 2

$\huge \purple {\tt{Question}}$

The breadth of a rectangular field is twice its length. If the area of the field is 1058 m², find the cost of

fencing it at rupees 35 per m.

$\huge \purple {\tt{Answer}}$

The cost of fencing is rs 4830.

$\purple {\tt{Explanation}}$

Consider length of the rectangular field = l meters,

∵ Breadth is twice its length.

So, width = 2l,

Thus, area = length × width

$= l \times 2l \\ = 2l^{2}$

According to the Question ,

${2l}^{2} = 1058 \\ \: \: \: \: {l}^{2} = \frac{1058}{2} \\ \: \: \: \: {l}^{2} = 529 \\ => l = \sqrt{529} = 23$

( Negative value will not consider because side can not be negative )

That is,breadth = 2(23) = 46,

Hence, perimeter of the field = 2(length + breadth) = 2(23+46) = 2(69) = 138 meters, If cost of fencing for 1 meter = 35 rupees, Then the cost of fencing 138 meters = 138 × 35 = 4830 rupees.

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