Question

the break applied to a car produce an acceleration of 6 metre per square in the opposite direction to the motion if the car takes 2 seconds to stop after the application of break calculate the distance it travel during this time​

Answer 1

Answer:

The distance travelled by the car during this time is 12 m.

Explanation:

a = -6 m/s^2

t = 2 seconds

v = 0 m/s

u = ??

s = ??

Using first equation of motion, i.e., v = u + at, we get :-

=> 0 = u + (-6 m/s^2 x 2 seconds)

=> 0 = u + (-12 m/s)

=> 12 m/s = u

=> u = 12 m/s

Now, using second equation of motion, we get:-

s = ut + 1/2 at^2

s = [(12 x 2) + 1/2 (-6)(2)^2] metre

s = [24 + 1/2 (-6)(4)] metre

s = [24 + 1/2 (-24)] metre

s = [24 + (-12)] metre

s = 12 metre.

Hence, the car travelled 12 metre.

I hope it help you.