Question

the Breakers applied to the car produce an acceleration of 15 metre per second in the opposite direction to the motion if the car takes 2 second to stop after the application of Breakers calculate the distance it travel during this time​

Answer 1

Explanation:

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Answer 2

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answers-30 m

Concept used⤵

↪NEWTONS 2nd Law

$v {}^{2} - u {}^{2} = 2as$

↪NEWTONS 3rd Law

$s = ut \: + \frac{1}{2} at {}^{2}$

Explanation⤵

Given

a= - 15 m/s2 ____(opposite drxn)

t=2 sec

v=0

Above u go✌