The breaking strength of a string connecting wall and block b is 175 N , find the maximum magnitude of block A for which the system will be stationary. The block b weighs 700 N
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Tsin30= weight of A
Tcos30=175 (breaking strength of the string)
From the equations you get weight of block $$A = 175/√3 N$$
Hence,
Answer- 175/√3N
Tcos30=175 (breaking strength of the string)
From the equations you get weight of block $$A = 175/√3 N$$
Hence,
Answer- 175/√3N
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