Question

the breaking strength of astring 2.5m long is 100N what is the maximum rpm at which the string can retain a 2kg mass attached to its​

Answer 1

Answer:

The maximum rpm = 11.1803398875

Explanation:

Mass of stone (m)= 2kg

radius(r)= length of rope = 2.5m

Maximum tension(T) = 100N

The maximum tension acts as the centripetal force for the circular motion of the stone.

Let v be the maximum velocity.

Hence,F = T = mv²/r

➜ v²= Tr/m

➜ V²= (100×2.5)/2

➜ V² = 125

➜ V = 11.1803398875