Question

The breaking tension of a string is 50 N. A body of

mass 1 kg is tied to one end of a 1 m long string

and whirled in a horizontal circle. The maximum

speed of the body should be :

(A) 5 2 m/s (B) 10 m/s

(C) 7.5 m/s (D) 5 m/s​

Answer 1

Answer:

5 √ 2 m / sec

Explanation:

Given :

Breaking tension of a string = 50 N

Mass of body = 1 kg

Radius r = 1 m

We have :

F = m v² / r

But here :

T =  m v² / r

50 = 1 ×  v² / 1

v² = 50

v = 5 √ 2 m / sec

Therefore , maximum  speed of the body should 5 √ 2 m / sec.

Answer 2

$\huge\underline{\underline{\bf \orange{Question-}}}$

The breaking tension of a string is 50 N. A body of mass 1 kg is tied to one end of a 1 m long string and whirled in a horizontal circle. The maximum speed of the body should be :

$\huge\underline{\underline{\bf \orange{Solution-}}}$

$\large\underline{\underline{\sf Given:}}$

• Breaking Tension ( T ) = 50N
• Mass ( m ) = 1 kg
• Lenght of string ( r ) = 1m

$\large\underline{\underline{\sf To\:Find:}}$

• Maximum Speed ( v )

✪$\large{\boxed{\bf \blue{T = \dfrac{mv^2}{r}}}}$

$\implies{\sf 50=\dfrac{1×v^2}{1}}$

$\implies{\sf v^2 = 50}$

$\implies{\bf\red{Speed ( v) = 5\sqrt{2}}}$

$\huge\underline{\underline{\bf \orange{Answer-}}}$

Speed of body should be ${\bf \red{5\sqrt{2}}}$.