Question

The breaks applied to a train moving at 90km/h produce a retardation of 5m/s^2 what will be the distance it covers to a stop

Answer 1

initial velocity=90kmph  =25mps.use formula v²=u²-2as0=25²-2*5s625=10ss=62.5m

Answer 2

the answer is 62.5 metre please mark me brainliest