Question

The bus fare in a city is as follows. For the first five kilometres the fare is `10 and for the subsequent distance it is `2 per km. Taking the distance covered as x km and total fare as `y, write a linear equation for this information and draw its graph. What will the bus fare for 10 km and 19 km.

Answer 1

Answer:

10km = Rupees 20

19km = Rupees 38

Step-by-step explanation:

The previous answer giver's answer was right. She / he just wrote 83 instead of 38. Equation formed is the same, i.e, y = 10 + 2(x - 5)

Put the values wanted like 10 or 19 in place of total distance or X. And U will get ur answer. No different process is their. For the graph. Find values of x and y by the common trial method and draw.

Making it EASY for u:- y = 2x (from the equation itself)

Put x = 1 , 2,3 and so on. 3 minimum needed.

Hope it helps.

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Answer 2

Answer:

The bus fare for 10 km is Rs $20$ and for $19$ km is Rs $38$.

Step-by-step explanation:

Given:

Fare for the first five km = Rs $10$

Fare for subsequent distance per km = Rs $2$

Distance covered = x km

Total fare = y

• Since,  for the first five km, the fare is Rs 10, and the total distance traveled is x km, the distance for which the fare needs to be calculated is x - 5.

• The fare for the subsequent distance per km is Rs $2$, therefore for

        (x - 5) km, the fare becomes  $2 (x-5)$.

• The total fare given in the question is y.

$\implies 10+2(x-5)=y$

$\implies 10+2x-10=y$

$\implies2x=y$

The equation for this is  $2x=y.$

The graph for this equation is plotted below.

$\implies$ For the distance, x = $10$ km, fare, y =  $2x$

                                                        =  $2(10)$

                                                        = Rs $20$

$\implies$ For the distance, x = $19$ km, fare, y =  $2x$

                                                        =  $2(19)$

                                                        = Rs $38$

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