Question

The bus fare in a city is as follows. For the first five kilometres the fare is `10 and for the subsequent distance it is `2 per km. Taking the distance covered as x km and total fare as `y, write a linear equation for this information and draw its graph. What will the bus fare for 10 km and 19 km.​

Answer 1

Given: The distance covered as x km and total fare is Rs. y.

Total fare =the fare for first km + the fare of the remaining distance

$y = 8 + 5 \times (x - 1)$

$y = 8 + 5x - 5$

$y = 3 + 5x$

For graph,

Putting x=0, we have y=3+5(0)=3

Putting x=1, we have y=3+5(1)=8

Putting x=2, we have y=3+5(2)=13

Hence,(0,3),(1,8) and (2,13) are solutions of equation.

The graph is as shown :

Answer 2

$Given: The distance covered as x km and total fare is Rs. y.</p><p></p><p>Total fare =the fare for first km + the fare of the remaining distance</p><p></p><p>y = 8 + 5 \times (x - 1)y=8+5×(x−1)</p><p></p><p>y = 8 + 5x - 5y=8+5x−5</p><p></p><p>y = 3 + 5xy=3+5x</p><p></p><p>For graph,</p><p></p><p>Putting x=0, we have y=3+5(0)=3</p><p></p><p>Putting x=1, we have y=3+5(1)=8</p><p></p><p>Putting x=2, we have y=3+5(2)=13</p><p></p><p>Hence,(0,3),(1,8) and (2,13) are solutions of equation.</p><p></p><p>The graph is as shown</p><p></p><p>$