Question

the bush arrives at B at 17:18 hours .if it leaves at 15:36 hours .distance between them is 46km. find the average speed of bus from A to B?​

Answer 1

Answer:

The distance covered is \frac{1445}{2}

2

1445

km.

The time taken is \frac{17}{2}

2

17

hours.

The relation between time, distance and speed is

\text{Speed}=\frac{\text{Distance}}{\text{Time}}Speed=

Time

Distance

\text{Speed}=\frac{\frac{1445}{2}}{\frac{17}{2}}Speed=

2

17

2

1445

\text{Speed}=\frac{1445\times 2}{2\times 17}Speed=

2×17

1445×2

\text{Speed}=85\text{ km/hr}Speed=85 km/hr

Therefore, Speed of the train is 85 km/hr.