the bush arrives at B at 17:18 hours .if it leaves at 15:36 hours .distance between them is 46km. find the average speed of bus from A to B?
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Answer:
The distance covered is \frac{1445}{2}
2
1445
km.
The time taken is \frac{17}{2}
2
17
hours.
The relation between time, distance and speed is
\text{Speed}=\frac{\text{Distance}}{\text{Time}}Speed=
Time
Distance
\text{Speed}=\frac{\frac{1445}{2}}{\frac{17}{2}}Speed=
2
17
2
1445
\text{Speed}=\frac{1445\times 2}{2\times 17}Speed=
2×17
1445×2
\text{Speed}=85\text{ km/hr}Speed=85 km/hr
Therefore, Speed of the train is 85 km/hr.
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