The % by volume of C4H10 in a gaseous mixture of C4H10 ,CH4 & CO is 40 . When 200ml of the mixture is burnt in excess of O2. Find the volume (in ml) of CO2 produced. (A) 220 (B) 340 (C) 440 (D) 560
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Answered by
56
(C) 44 0 ml
There is one Carbon atom in the molecule of CO2.
Volume of C4 H10 in the mixture = 80 ml
volume of CO2 produced by combustion of C4H10 = 4 * 80 = 320 ml
as there are 4 Carbons in each molecule.
volume of CH4 + CO in mixture = 120 ml
volume of CO2 produced = 120 ml
Total volume of CO2 = 320 + 120 = 440 ml
There is one Carbon atom in the molecule of CO2.
Volume of C4 H10 in the mixture = 80 ml
volume of CO2 produced by combustion of C4H10 = 4 * 80 = 320 ml
as there are 4 Carbons in each molecule.
volume of CH4 + CO in mixture = 120 ml
volume of CO2 produced = 120 ml
Total volume of CO2 = 320 + 120 = 440 ml
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Answered by
11
Answer:
C) 440
Explanation: for correct and easy step of answer prefer above solution
For this question we must know the relationship that
Moles is directly proportional to volume
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