Math, asked by shristyjalan1234, 3 months ago


The C.P. of an article is Rs.x and it's S.P. is Rs.y. The
C.P. is increased by 20% but the S.P. remains constant.
For a weight of 12 kgs how much the trader should
weigh so that he is having the same percentage profit?
(a) 15 kg (b)10 kg (c) 8 kg
(d) 14.4 kg (e) 9 kg

Answers

Answered by Anonymous
0

Answer:

14.4kg Tiply

then

division of

Answered by amitnrw
1

Given : The C.P. of an article is Rs.x and it's S.P. is Rs.y.

The C.P. is increased by 20% but the S.P. remains constant.

To Find : For a weight of 12 kgs how much the trader should

weigh so that he is having the same percentage profit?

(a) 15 kg (b)10 kg (c) 8 kg

(d) 14.4 kg (e) 9 kg

Solution:

The C.P. of an article is Rs.x

a weight of 12 kgs  

CP  = 12x

SP = 12y

Profit  %  = 100 *  ( 12y - 12x)/12x  = 100 (y - x)/x

C.P. is increased by 20%

New CP   = 12x + (20/100)12x  = 14.4x

New SP  =  14.4x +   14.4x(100 (y - x)/x) /100  

= 14.4x + 14.4y - 14.4x

= 14.4y

Hence to be weighed = 14.4y/y  = 14.4  kg

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