Math, asked by Anonymous, 3 months ago

The calendar for the year 1753 is the same as for

Answers

Answered by Anonymous
2

Answer:

But changing calendars left everyone with a problem. Since the Gregorian calendar accounted more accurately for leap years, it was 11 days ahead of the Julian calendar by 1752. To correct this discrepancy and align all dates, 11 days had to be dropped when the switch was made.

Step-by-step explanation:

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Answered by RvChaudharY50
1

Given :- The calendar for the year 1753 is the same as for ?

Answer :-

1753 ÷ 4 = 53 ÷ 4 = Remainder 1 .

checking,

→ 1753 = 1 odd day = sum 1

→ 1754 = 1 odd day = sum 2

→ 1755 = 1 odd day = sum 3

→ 1756 = 2 odd day = sum 5

→ 1757 = 1 odd day = sum 6

→ 1758 = 1 odd day = sum 7 = Remainder 0 .

then,

Calander of 1753 will be same as 1759 .

Learn more :-

2.Given that on 10th June 1950 was Tuesday, what was the day on 10th June 1550?

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