Question

the cap of a joker is of right circular cone whose radius of base is 7 cm and height is 24 cm find the area is of cardboard required to make 10 such caps

Answer 1

According to the Question :-

Radius of cone = 7cm

Height of cone = 24cm

Slant height

$\bf\huge = \sqrt{(24)^2 + (7)^2}$

$\bf\huge = \sqrt{576 + 49}$

$\bf\huge = \sqrt{625}$

l = 25cm

Area of joker's cap = πrl

$\bf\huge = \frac{22}{7} \times 7\times 25$

= 22 × 25

= 550 cm²

Curved surface area of 1 joker's cap

= 550cm²

Curved surface area 10 joker's cap

= 10 × 550

= 5500 cm²

Answer 2

$\underline{\mathfrak{\huge{The\:Question:}}}$

The cap of a joker is of right circular cone whose radius of base is 7 cm and height is 24 cm. Find the area is of cardboard required to make 10 such caps.

$\underline{\mathfrak{\huge{Your\:Answer:}}}$

$\sf{Given:}$

Radius of the base of the cone = 7 cm

Height of the right circular cone = 24 cm

Number of caps needed = 10 caps

$\sf{Solution:}$

Length of the right circular cone :

$\tt{l = \sqrt{h^{2} + r^{2}}}$

=》 Length of the cone = $\tt{\sqrt{24^{2} + 7^{2}}}$

=》 Length = $\tt{sqrt{625}}$

=》 Length = 25 cm

Curved Surface Area = $\tt{\pi r l}$

=》 Curved Surface Area = $\tt{\frac{22}{7} \times 7 \times 25}$

=》 Curved Surface Area = $\tt{550 cm^{2}}$

For 10 caps = 550 × 10

=》 $\tt{5500 cm^{2}}$ is needed for 10 caps.