Question

The capacity and the base area pf a right circular conical vessel are 9856 cm³ and 616 cm² respectively.find the curved surface area of the vessel.

Answer 1

Answer:

$\huge\boxed{Hey\:mate\:here\:is\:your\:answer:}$

$\huge\boxed{Solution:}$

Let the radius of the base and height of the conical vessel be r cm and h cm respectively.

∴$\large\boxed{\pi r^2 =616} \\\\\large\boxed{And}\\\\\large\boxed{\frac{1}{3}\pi r^2h=9856 }$

→$\large\boxed{r^2=\frac{616*7}{22}=196} \\\\\large\boxed{And}\\\\\large\boxed{\frac{1}{3}*616*h=9856}$

→$\large\boxed{r=14cm}\\\\\large\boxed{And}\\\\\large\boxed{h=48cm}$

→If the slant height of the vessel be l m, then l²=h²+r²,

→$\large\boxed{l=\sqrt{(48)^2+(14)^2} = \sqrt{2500} \:cm=50\:cm.}$

∴Curved surface area of the vessel

$\large\boxed{=\pi rl=\frac{22}{7}*14*50\:cm^2=2200\:cm^2 }$.

$\huge\boxed{\boxed{\boxed{Hope\:it\:helps\:you}}}$

Answer 2

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