the capacity of a rectangular tank is 5.2 m^3 and the area of its Base is 2.6 * 10^4 cm^2; find its height or depth.
Answers
Answered by
120
hello users ....
solution:-
we know that:
volume of cuboid = l×b×h
where l is the length of rectangular tank or cuboid ,b is the breadth , and h is the height ,
and
1m² = 10⁴ cm²
also
the area of rectangle = l×b
According to given :
volume = l×b×h = 5.2m³
and
area of it's base = l× b = 2.6×10⁴ cm²
=> l× b = 2.6 m²
=> volume of cuboid
=> (area of base ) × h = 5.2 m³
=> h = 5.2 / 2.6 = 2 m
hence,
height of rectangular tank = 2m or 200 cm Answer
✡ hope it helps :)
solution:-
we know that:
volume of cuboid = l×b×h
where l is the length of rectangular tank or cuboid ,b is the breadth , and h is the height ,
and
1m² = 10⁴ cm²
also
the area of rectangle = l×b
According to given :
volume = l×b×h = 5.2m³
and
area of it's base = l× b = 2.6×10⁴ cm²
=> l× b = 2.6 m²
=> volume of cuboid
=> (area of base ) × h = 5.2 m³
=> h = 5.2 / 2.6 = 2 m
hence,
height of rectangular tank = 2m or 200 cm Answer
✡ hope it helps :)
Binson1:
the answer was very useful
Answered by
21
hi guys
as we know
1 m^3 =1000000 cm^3. or 10^6 cm^3
5.2 m^3 *10^6=5.2*10^6. cm^3
so volume =5.2*10^6 cm^3
l*b*h =volume
2.6*10^4*H=5.2*10^6
H=5.2*10^6 /2.6*10^4
H=2*10^2
H=200 cm or 2m
as we know
1 m^3 =1000000 cm^3. or 10^6 cm^3
5.2 m^3 *10^6=5.2*10^6. cm^3
so volume =5.2*10^6 cm^3
l*b*h =volume
2.6*10^4*H=5.2*10^6
H=5.2*10^6 /2.6*10^4
H=2*10^2
H=200 cm or 2m
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