Question

the car makes an displacement of 100 m and 200 m then towards north.the magnitude and direction of resultant are respectively​

Answer 1

Answer:

223.7m, $tan^{-1} (2)$, Nof E

Explanation:

$Net\\displacement \\S = \sqrt{200^{2} +100^{2} } \\ = \sqrt{50000} \\= 223.7 m\\tan\theta = \frac{200}{100} \\\theta = tan^{-1} (2)\\direction will be North to East$