Question

The car starts from rest attains a speed of 36 km in 10 sec calculate the acceleration of the car

Answer 1

intial velocity = 0 m/s
final velocity = 36km/h = 36000/3600 = 10m/s
time = 10sec
by applying Ist equation of motion 
            v=u+at
        10=0+a*10
     10/10 =a
 acceleration is 1m/s²

Answer 2

✬ Acceleration = 1 m/s² ✬

Explanation:

Given:

• A car starts from rest (u) = 0 m/s.
• Car attained a speed of 36 km (v) = 36 km/h
• Time (t) taken by car = 10 seconds.

To Find:

• What is the acceleration (a) of car ?

Formula to be used:

• First law of motion
• v = u + at

Solution: Changing 36 km/h in m/s. For this multiply 36 by 5/18

➯ ( 36 $\times$ 5/18 ) m/s

➯ ( 2 $\times$ 5 ) m/s

➯ 10 m/s ( v = Final Velocity )

Putting the values on formula

$\implies{\rm }$ v = u + at

$\implies{\rm }$ 10 = 0 + a $\times$ 10

$\implies{\rm }$ 10 = 10a

$\implies{\rm }$ 10/10 = a

$\implies{\rm }$ 1 m/s² = a

Hence, the acceleration of the car is 1 m/s².