The equation of line passing through the point of intersection of the lines 4x-3y-1=0
and 5x-2y-3=0
and parallel to the line 2y-3x+2=0,
is [RPET 1985, 86, 88]
A) x-3y=1 B) 3x-2y=1 C) 2x-3y=1 D) 2x-y=1
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Answered by
5
THE POINT OF INTERSECTION OF THE LINES
4X-3Y-1=0&5X-2Y-3=0 IS (1,1) =(X1,Y1) IT'S PARALLEL TO THE LINE 2Y-3X+2=0 WHOSE SLOPE IS 3/2
SINCE ITS PARALLEL THE SLOPES ARE SAME
BY USING SLOPE INTERCEPT FORM i.e
(y-y1)=m(x-x1)
we get option B
4X-3Y-1=0&5X-2Y-3=0 IS (1,1) =(X1,Y1) IT'S PARALLEL TO THE LINE 2Y-3X+2=0 WHOSE SLOPE IS 3/2
SINCE ITS PARALLEL THE SLOPES ARE SAME
BY USING SLOPE INTERCEPT FORM i.e
(y-y1)=m(x-x1)
we get option B
Answered by
3
Answer:
just go through it mate
Step-by-step explanation:
hope it helps u well
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