Math, asked by dishari14, 2 months ago


The cartesian equations of a line are x = ay +b, z = cy + d. Find its direction ratios and
reduce it to vector form.

Answers

Answered by armaanshaikh14
1

Step-by-step explanation:

The cartesian equation of the given line is x=ay+b,z=cy+d It can be re-written as

a

x−b

=

1

y−0

=

c

z−d

Thus, the given line passes through the point (b,0,d) and its direction ratios are proportional to a,1,c. It is also parallel to the vector

b

=a

i

+

j

+c

k

We know

that the vector equation of a line passing through a point with position vector

a

and parallel to the vector

b

is

r

=

a

b

Vector equation of the required line is

r

=(b

i

+0

j

+d

k

)+λ(a

i

+

j

+c

k

)

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