Question

The catalytic decomposition of phosphine 4 PH3(g) ---> P4 + 6H2(g) has rate law as rate = k[ PH3]. the rate constant is 6.0 x 10^-4 s^-1 at 300 k and E^a is 3.05 x 10^5 J/mol. What is the value of rate constant at 310 k?

Answer 1

6.8=4.876con^^hope the

Answer 2

This is the answer : k2 = 3.098 × 10^-2