The ceiling of a long hall is 25 m high. What is the maximum horizontal distance that a ball thrown with a speed of 40 m s⁻¹ can go without hitting the ceiling of the hall?
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Hii dear,
# Answer- 148.3 m
# Given-
H = 25 m
u = 40m/s
# Solution-
For a ball hitting ceiling of roof-
H = u^2(sinθ)^2 / 2g
25 = 40^2(sinθ)^2/ (2×10)
(sinθ)^2 = 25×2×10/40×40
(sinθ)^2 = 0.3125
sinθ = 0.5590
θ = 34°
Horizontal distance at θ=34° is,
R = u^2sin2θ / g
R = 40^2.sin68 / 10
R = 148.3 m
Maximun horizontal distance without touching the roof is 148.3 m.
Hope that helped you...
# Answer- 148.3 m
# Given-
H = 25 m
u = 40m/s
# Solution-
For a ball hitting ceiling of roof-
H = u^2(sinθ)^2 / 2g
25 = 40^2(sinθ)^2/ (2×10)
(sinθ)^2 = 25×2×10/40×40
(sinθ)^2 = 0.3125
sinθ = 0.5590
θ = 34°
Horizontal distance at θ=34° is,
R = u^2sin2θ / g
R = 40^2.sin68 / 10
R = 148.3 m
Maximun horizontal distance without touching the roof is 148.3 m.
Hope that helped you...
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