Question

The cell in which the following reaction occurs: 2Fe3+ (aq) + 21 (aq) → 2Fe2+ (aq)+1, (s) has Ecell = 0.236 V at 298 K. Calculate the standard Gibbs energy and the equilibrium constant of the cell reaction. Can't we find equilibrium constant from Nernst equation
for this question.
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Answer 1

Answer:

ΔG=nFE

∘

=−2×96500×0.236=−45.548kJ

logK=

2.303RT

nFE

∘

=

0.0591

2×0.236

=7.986

K=(10)

7.986

=96827785.6

=9.68×10

7