The cell, Zn 1 Zn2+ (1M) || Cu2+ (1M) | Cu
(E =1.10v) was allowed to be completely
discharged at 298K. The relative concentration of
Zn2+ to Cu2+, i.e.
is:
(Cu
)
(a)37.3
.69.65 x 104
(b) 10373
(d) Antilog (24.08)
Answers
Answered by
1
Answer:
antilog (24.7)
Explanation:
because zn2+cu2+ie arth folmula and this is answer
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