Question

The center of a circle is (a+2, a-1).
find a
if the circle passes through
(2,-2) and (8-2)​

Answer 1

Sol: Points on the circle are (2, -2) and (8, -2) Centre of the circle = (a+2, a-1) Distance between (a+2, a-1) and (2, -2) = Distance between (a+2, a-1) and (8, -2) √[(2-a-2)2 + (-2-a+1)2] = √[(8-a-2)2 + (-2-a+1)2] √[(-a)2 + (-1-a)2] = √[(6-a)2 + (-1-a)2] Squaring on both sides, a2 + 1 + a2 + 2a = 36 + a2 - 36a + 1 + a2 + 2a 2a + 1 = 37 - 34a 36a= 36 a = 1 Hence, the value of a is 1.

Answer 2

Answer: I have tried to solve....

May this will help you...

If there is any confusion tell