The center of a circle is located at (3, 8), and the circle has a radius that is 5 units long. What is the general form of the equation for the circle?
A.
x2 + y2 − 6x − 16y + 48 = 0
B.
x2 + y2 − 6x − 16y − 25 = 0
C.
x2 + y2 + 6x + 16y + 48 = 0
D.
x2 + y2 + 6x + 16y − 25 = 0
Answers
Answered by
1
answer is A. x2+y2-6x-16y+48
Answered by
0
Answer:
.
Step-by-step explanation:
Similar questions