Question

The Center of a wheel rolling on a plane surface moves with a speed v0. A particle on the rim of the wheel at the same level as the center will be moving at a speed

(a) zero
(b) v0
(c) √2v0
(d) 2v0.

Answer 1

Answer ⇒ Option (c).

Explanation ⇒

Assuming that the radius of the wheel be r.

∴ We know that the angular speed of the wheel will be given by the Relation,

⍵ = v₀/r

where,

v₀ is the speed and r is the distance.

We know that the particle on the rim of the wheel at the same level as the center will have a vertical speed = ⍵r

= v₀/r × r

= v₀

Also, horizontal speed is also equals to the v₀.

Therefore, the resultant speed will be given by,

R = $\sqrt{(v_0)^2 + (v_0)^2}$

= $\sqrt{2(v_0)^2}$

= v₀√2

Hence, Option (c). is correct.

Hope it helps.

Answer 2

Answer:

answer

(c)

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