Question

the center of the circle is (-4.2) if ond end of the diameter is (-3.7)find the other end​

Answer 1

Step-by-step explanation:

-4 = {x+3}/2

x+3 = -8

x = -11

2 = { y -7 }/2

y -7 = 4

y = 11

{ -11,11} answer

Answer 2

$\huge\rm\underline\purple{Question :-}$

The center of the circle is (-4, 2) if one end of the diameter is (-3, 7). Find the other end .

$\huge\rm\underline\orange{Answer :-}$

$\sf Given\begin{cases} &\sf{Center\;of\;the\; circle \; =\be{(-4,2)}}\\&\sf{One\;end\;of\;the\;diameter\; =\bf{(-3,7)}}\end{cases}$

$\pink\bold{Let\: x= \:-4 \:and \:y \:= \:2}$

$\pink\bold{Let\: x1 = \:-3\: and\: y1\: =\: 7}$

$\red{\underline\bold{To\:Find,}}$

• Other end of the diameter = ❓
• i.e x2 and y2 =❓

$\blue{\underline\bold{Using\:the\:formula,}}$

$\boxed{ \sf \purple{ M(x,y)\: =\: [\frac{x1+x2}{2}\:, \frac{y1+y2}{2} \;]}}$

⇒(-4,2) = $\;[\frac{ -3+x2}{2}\:,\frac{7+y2}{2}]$

⇒$\frac{ -3+x2}{2}$ = -4

⇒-3 + x2 = -8

⇒x2 = -8 + 3

⇒x2 = -5

$\blue{\underline\bold{And,}}$

⇒$\frac{7+y2}{2}$ = 2

⇒7 + y2 = 4

⇒y2 = 4 - 7

⇒y2 = -3

$\pink{\underline\bold{ ∴ \:The\:other\:end\:of\:the\: diameter\: is \: (-5,-3).}}$

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