Question

The central angle of a sector of circle of
area 9 sq.cm is 60°, the perimeter of the
sector is
A) 1 B) 3+ C) 6+ D) 6​

Answer 1

Answer:

Ans: 6 cm

Area of Sector = xπr^2/360

9=60x22xr^2/360x7

r^2 = 17.18...

r=v17.18=2 cm

Arc length x2πr/360

60x2x22x2/360x 7=2 cm

Perimeter of the sector=2 radius + Arc length=2x2+2=6cm. Ans(D)