The Central Hall of a school is 18 M long and 12.5 M wide a carpet is to be laid on the floor leaving the strip 50 cm wide near the walls and covered find the area of the carpet and also the uncovered portion
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Area of the hall=(18+12.5)2
=61 M
Now the area of the uncovered region is
=2(18*.5+12.5*.5)
=31.5M
Area of the carpet =61-31.5=29.5M
=61 M
Now the area of the uncovered region is
=2(18*.5+12.5*.5)
=31.5M
Area of the carpet =61-31.5=29.5M
wrobg answer
wrong answer
answer is 29.5
it's OK my subtraction is wrong see it
I correct it
bro now see it
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