The centre of a circle is (2a, a - 7). Find the values of a if the circle passes through
(11,-9) and has diameter 10√2 units.
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Answer: 5,3
Step-by-step explanation:
the diameter is 10√2
then radius =5√2
√(2a-11)²+(a-7+9)²=5√2
(2a-11)²+(a+2)²=(5√2)²
4a²-44a+121+a²+4a+4=50
5a²-40a+75=0
a²-8a+15=0
(a-3)(a-5)=0
a=3,5
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