Question

The centre of a circle whose end points of a diameter are (-6, 3) and (6, 4) is​

Answer 1

Step-by-step explanation:

If the endpoints of the diameter are (-6 , 3) and (6 , 4) ,

then the centre of the circle would be the midpoint of this line since 2 x radius = diameter.

midpoint of the X coordinates

= ( - 6 + 6) /2

= 0

midpoint of the Y coordinates

= ( 3 + 4 )/2

= 7/2

= 3.5

So the coordinates of the centre of the circle are ( 0 , 3.5 )

Answer 2

Given:

The end points of a diameter of a circle are:

(x1 , y2) = (-6 , 3)

(x2 , y2) = (6 , 4)

To Find:

Center of a circle = ?

Solution:

As we know,

$Mid \ points \ of \ X-axis ,$

$X= \frac{x1+x2}{2}$

On putting the values, we get

$X=\frac{-6+6}{2}$

$X=0$

$Mid \ points \ of \ Y-axis,$

$Y=\frac{y1+y2}{2}$

On putting the values, we get

$Y=\frac{3+4}{2}$

$Y=\frac{7}{2}$

Thus, the center co-ordinates of a circle will be "(0 , 7/2)".