Question

the centre of a circle whose end points of a diameter are (-6,3) and (6,4)​

Answer 1

Answer: mark me brainliest

Step-by-step explanation:

Answer 2

AnswEr:

Center Of the circle is 0 and $\sf\dfrac{7}{2}$

Step by Step Explanation:-

Given:-

Ends Points of the Diameter are (-6,3) & (6,4).

Then, Center of the Circle

$:\implies\sf\dfrac{x_1 + x_2}{2} \;and \; \dfrac{y_1 + y_2}{2}$

Here, x1 = -6 , x2 = 6

y1 = 3 , y2 = 4

Putting Values:-

$:\implies\sf\; \dfrac{-6 + 6}{2} \;,\; \dfrac{3 + 4}{2}$

$:\implies\sf\; \dfrac{0}{2}\; , \;\dfrac{7}{2}$

$:\implies\sf\;( 0 \; , \; \dfrac{7}{2})$

$\bold{\underline{\sf{\pink{So,\; the \; Center\; of \; the \; Circle\; is \; 0 \; and \;\dfrac{7}{2}}}}}$

$\rule{150}3$