Question

The centre of a circle with (1, 2) and (7, -4), as end points of the diameter is (1, 2) మరియు (7, 4) లు వ్యాసాగ్రాలు గా గల వృత్త కేంద్రం (1) (-4, 1) (2) (4, -1) (3) (4, -1) (4) (4, 1)​

Answer 1

Answer:

Basic Algebra Identities

(a + b)2 = a2 + b2 + 2ab

(a – b)2 = a2 + b2 – 2ab

a2 – b2 = (a + b)(a – b)

a2 + b2 = (a + b)2 – 2ab = (a – b)2 + 2ab

a3 + b3 = (a + b)(a2 – ab + b2)

a3 – b3 = (a – b)(a2 + ab + b2)

(a + b)3 = a3 + 3ab(a + b) + b3

(a – b)3 = a3 – 3ab(a – b) – b3

Answer 2

Answer:

The centre of the circle with the given end points of diameter is (4,-1)

Step-by-step explanation:

The proper question is ''The centre of a circle with (1,2) and (7,-4) as end points of the diameter is?''

Given that,for a circle the end points of the diameter are given as (1,2) and (7,-4) we are required to find the centre of the given circle.

The centre of a circle is the mid point of the diameter of circle.Hence,we are supposed to find the mid point of diameter using given points.

For any two points A(a,b) and B(c,d),the mid point is given by the relation as shown $M=(\frac{a+c}{2} ,\frac{b+d}{2} )$

Hence,the mid point of the given co-ordinates becomes

$(\frac{1+7}{2} ,\frac{2-4}{2} )=(4,-1)$

Therefore,The centre of the circle with the given end points of diameter is (4,-1)

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